Lab Report On Titration

TITRATION OF AN ACID (A PREPARED STANDARD SOLUTION OF KH?O?C?) AGAINST A BASE (NAOH) USING PHENOLPHTHALEIN AS AN INDICATOR BY GRACE The aim of this experiment is to fake a stock(a) solution of potassium hydrogen phthalate (KH?O?C?) and hence use it to calculate the submerging of atomic pattern 11 hydroxide by titrating the dit (KH?O?C?) against the ahead (NaOH). Before the whole experiment could take place, some limb were needed which included the following; A weighing balance, burette, pipette, a conical flask, clamp and then the setup was as to a lower place; THEORY To calculate for the moles of KH?O?C?, I utilize n (mol) =m (g)/M (gmol?? (JOHN young AND SADRU DAMJI, PG 6 OF CHAPTER 1.THIRD EDITION). Whereby m= muss of the vitriolic, M=molar pull in of the acid and n= twist of moles. Molar mass of KH?O?C? is 204.1g/mol and its mass is 1g accordingly=1g/204.1gmol?? n=0.0048996mol nurture more, to calculate for the immersion of the acid, I employ C(moldm?3.) =n (mol)/v (dm3) Whereby c= ducking, n=number of moles and v=volume utilise. (JOHN atomic number 19 AND SADRU DAMJI, PG 27.THIRD EDITION) Volume=0.1dm3 Concentration of acid =0.0048996mol/0.1dm3 =0.

049moldm?3 Also, to calculate for the total titre volume of the acid used, I summed up the ternary consistent values from my experiment and separate it by 3(sarps series, 2009) thus Average Titre volume= (19.60+19.60+19.60) 3 =19.60cm3 Also, to calculate for the concentrat! ion of sodium hydroxide, I used The dilution factor, C?v?=C?v? (JOHN GREEN AND SADRU DAMJI pg28, third edition) whereby C?=concentration of the acid used=0.049moldm?3 v?=volume of acid used (titre volume) =19.60cm3 C?=concentration of the base, v?=volume of the base used=10cm3 Therefore C?= (0.049*19.60)/10 C?=0.096 moldm?3 Therefore the concentration of sodium hydroxide is0.096 moldm?3 |Burette...If you want to propel up a full essay, order it on our website: OrderCustomPaper.com

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